LanguageInputWidget: Fix logic for checking if language exists

ve.init.platform.getLanguageName returns the language code
if no name is found, so use hasLanuageCode instead.

Change-Id: I0ae9b0b4a3b6b31bd63e461b5d09f6151df025f5

src/ui/widgets/ve.ui.LanguageInputWidget.js

@@ -173,8 +173,9 @@ ve.ui.LanguageInputWidget.prototype.setLangAndDir = function ( lang, dir ) {
 		lang = lang || '';
 		this.languageCodeTextInput.setValue( lang );
 		this.selectedLanguageLabel.setLabel(
-			ve.init.platform.getLanguageName( lang.toLowerCase() ) ||
-			ve.msg( 'visualeditor-languageinspector-widget-changelang' )
+			ve.init.platform.hasLanguageCode( lang.toLowerCase() ) ?
+				ve.init.platform.getLanguageName( lang.toLowerCase() ) :
+				ve.msg( 'visualeditor-languageinspector-widget-changelang' )
 		);
 		this.directionSelect.selectItemByData( dir );
 	} else {

tests/ve.test.utils.js

@@ -37,6 +37,9 @@
 		$wrapper[ 0 ].normalize();
 		return $wrapper.contents().toArray();
 	};
+	DummyPlatform.prototype.getLanguageCodes = function () {
+		return [ 'ar', 'en', 'es', 'fr', 'ru', 'zh' ];
+	};
 	DummyPlatform.prototype.getLanguageName = function ( lang ) {
 		return 'langname-' + lang;
 	};